117 lines
2.7 KiB
Go
117 lines
2.7 KiB
Go
package main
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import "fmt"
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func exercise1() func(int) int {
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fmt.Println("=== 练习1:基础闭包 ===")
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// 创建一个闭包函数,它捕获外部变量multiplier
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// 该闭包接收一个int参数并返回乘以multiplier的结果
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multiplier := 3
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____ := func(num int) ____ {
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return ____
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}
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return ____
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}
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func exercise2() func() int {
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fmt.Println("=== 练习2:闭包状态保持 ===")
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// 创建一个递增计数器闭包
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// 每次调用返回的函数时,计数器加1
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// 提示:使用匿名函数捕获外部变量
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count := ____
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____ := func() ____ {
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____
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return ____
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}
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return ____
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}
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func exercise3() func() int {
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fmt.Println("=== 练习3:斐波那契数列闭包 ===")
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// 创建一个生成斐波那契数列的闭包
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// 每次调用返回下一个斐波那契数
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// 数列: 0, 1, 1, 2, 3, 5, 8, 13, 21, 34...
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a, b := ____, ____
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____ := func() ____ {
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result := ____
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a, b = ____
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return ____
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}
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return ____
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}
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func exercise4() func(int) bool {
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fmt.Println("=== 练习4:闭包配置 ===")
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// 创建一个检查数字是否在范围内的闭包生成器
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// 该生成器接受min和max两个参数,返回一个检查函数
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// 检查函数判断输入数字是否在[min, max]范围内
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min := 10
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max := ____
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____ := func(num int) ____ {
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return num >= ____ && num <= ____
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}
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return ____
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}
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func exercise5(start int) func(int) int {
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fmt.Println("=== 练习5:闭包累加器 ===")
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// 创建一个累加器闭包
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// 从start开始,每次调用累加参数值
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// 提示:闭包应该能访问外部作用域的变量
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total := ____
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____ := func(n int) ____ {
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____
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return ____
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}
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return ____
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}
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func main() {
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fmt.Println("=== 闭包 练习 ===\n")
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add3 := exercise1()
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fmt.Printf("练习1结果: add3(4) = %d\n", add3(4))
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fmt.Printf("练习1结果: add3(5) = %d\n", add3(5))
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counter := exercise2()
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fmt.Printf("练习2结果: counter() = %d\n", counter())
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fmt.Printf("练习2结果: counter() = %d\n", counter())
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fmt.Printf("练习2结果: counter() = %d\n", counter())
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fib := exercise3()
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fmt.Printf("练习3结果: fib() = %d\n", fib())
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fmt.Printf("练习3结果: fib() = %d\n", fib())
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fmt.Printf("练习3结果: fib() = %d\n", fib())
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fmt.Printf("练习3结果: fib() = %d\n", fib())
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fmt.Printf("练习3结果: fib() = %d\n", fib())
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inRange := exercise4()
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fmt.Printf("练习4结果: inRange(15) = %t\n", inRange(15))
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fmt.Printf("练习4结果: inRange(5) = %t\n", inRange(5))
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fmt.Printf("练习4结果: inRange(20) = %t\n", inRange(20))
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accumulator := exercise5(100)
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fmt.Printf("练习5结果: accumulator(10) = %d\n", accumulator(10))
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fmt.Printf("练习5结果: accumulator(20) = %d\n", accumulator(20))
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fmt.Printf("练习5结果: accumulator(30) = %d\n", accumulator(30))
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}
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