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LeetCode/矩阵/3. 旋转图像.md
2025-10-02 22:14:32 +08:00

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# 旋转图像
## 题目
给定一个 n × n 的二维矩阵 matrix 表示一个图像。请你将图像顺时针旋转 90 度。
你必须在 原地 旋转图像,这意味着你需要直接修改输入的二维矩阵。请不要 使用另一个矩阵来旋转图像。
示例 1:
输入:matrix = [[1,2,3],[4,5,6],[7,8,9]]
输出:[[7,4,1],[8,5,2],[9,6,3]]
示例 2:
输入:matrix = [[5,1,9,11],[2,4,8,10],[13,3,6,7],[15,14,12,16]]
输出:[[15,13,2,5],[14,3,4,1],[12,6,8,9],[16,7,10,11]]
提示:
n == matrix.length == matrix[i].length
1 <= n <= 20
-1000 <= matrix[i][j] <= 1000
## 思路
- 观察特点
- 对角线交换
- 左右镜像交换
## 代码
```java
class Solution {
public void rotate(int[][] matrix) {
// Init: n(length)
int n = matrix.length;
// Traverse 1
for (int i = 0; i < n; i++) {
for (int j = i; j < n; j++) {
int tmp = matrix[i][j];
matrix[i][j] = matrix[j][i];
matrix[j][i] = tmp;
}
}
// Traverse 2
for (int i = 0; i < n; i++) {
for (int j = 0; j < n/2; j++) {
int tmp = matrix[i][j];
matrix[i][j] = matrix[i][n - j - 1];
matrix[i][n - j - 1] = tmp;
}
}
}
}
```